CTET Pariksha 2019 | CTET Online Application[ctet.nic.in] Jahirat 2019

CTET Pariksha 2019 | CTET Online Application[ctet.nic.in] Jahirat 2019

CTET Pariksha 2019 | CTET Online Application[ctet.nic.in] Jahirat 2019.Central Board of Secondary Education, Delhi will be conducting the Central Teacher Eligibility Test (CTET- Dec 2019) for appointment as a teacher in classes I to VIII. 

CTET Central Teacher Eligibility Test Dec 2019

You will get here complete detail about  CTET Exam 2019| CTET Online Application[ctet.nic.in] Jahirat 2019 procedure, important dates, application fees, age limit, qualification, the number of vacancies, pay scale and important links. 

[CTET] केंद्रीय शिक्षक पात्रता परीक्षा 2019 

CTET Pariksha 2019 | CTET Online Application[ctet.nic.in] Jahirat 2019
CTET Pariksha 2019 | CTET Online Application[ctet.nic.in] Jahirat 2019

नौकरी स्थान (Job Place):

  • केंद्रीय माध्यमिक शिक्षा बोर्ड[Central Board of Secondary Education]

पद भरती पद्धत (Posting Type):

  • Examination

जाहिरात संख्या/क्र. (Advertisement Number):

  • Employment Notice No. CTET/Dec 2019
  • Advertisement from an official website portal https://ctet.nic.in

एकून पद संख्या (Total Posts):

  • — Posts

Post Details For CTET Pariksha 2019

पद नाम (Job Details):

  • शिक्षक [1 ली ते 5 वी ] /Teacher (for Classes I-V) (Primary Stage)
  • शिक्षक [6वी  ते 8 वी ] /Teacher (for Classes VI-VIII) (Elementary Stage)
  • For more details read official Notification Advertisement.

शैक्षणिक पात्रता (Educational Qualification):
शिक्षक [1 ली ते 5 वी ] /Teacher (for Classes I-V) (Primary Stage)

  • Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 2- year Diploma in Elementary Education (by whatever name known) OR
  • Senior Secondary (or its equivalent) with at least 45% marks and passed or appearing in final year of 2- year Diploma in Elementary Education (by whatever name known) OR
  • Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 4- year Bachelor of Elementary Education (B.EI.Ed). OR
  • Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 2- year Diploma in Education (Special Education) OR
  • Graduation with at least 50% marks and Bachelor of Education (B.Ed).

शिक्षक [6वी  ते 8 वी ] /Teacher (for Classes VI-VIII) (Elementary Stage)

  • Graduation and passed or appearing in final year of 2-year Diploma in Elementary Education (by whatever name known) OR
  • Graduation with at least 50% marks and passed or appearing in 1-year Bachelor in Education (B.Ed) OR
  • Graduation with at least 45% marks and passed or appearing in 1-year Bachelor in Education (B.Ed), in accordance with the NCTE (Recognition Norms and Procedure) Regulations issued from time to time in this regard OR
  • Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 4- year Bachelor in Elementary Education (B.EI.Ed) OR
  • Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 4- year B.A/B.Sc.Ed or B.A.Ed/B.Sc.Ed. OR
  • Graduation with at least 50% marks and passed or appearing in 1-year B.Ed. (Special Education) OR
  • Any candidate having qualified B.Ed. Programme recognized by the NCTE is eligible to appear in TET/CTET.
  • For more details read official Notification Advertisement.

अर्ज पद्धत (How to Apply):

  • Online Application / ऑनलाइन  अर्ज.
  • Interested and Eligible Candidates may Apply Only Online through CBSC website www.ctet.nic.in from 19.08.2019 to 18.09.2019.

Age Limit For CTET Pariksha 2019

वयमर्यादा (Age Limit): 

  • For more details read official Notification Advertisement.

अर्ज शुल्क (Application Fee):
अर्ज फीस (Application Fees):

  • OPEN/OBC प्रवर्ग:
    • पेपर 1 किंवा 2 करीता – ₹ 700/-
    • दोन्ही पेपर करीता – ₹ 1200/-
  • SC/ST/PWD(अपंग) प्रवर्ग:
    • पेपर 1 किंवा 2 करीता – ₹ 350/-
    • दोन्ही पेपर करीता – ₹ 600/-
  • Pay the Examination Fee through –
    • Debit Card, Credit Card, Net Banking or
    • Pay Offline Through E Challan.

Selection Process CTET Online Application[ctet.nic.in] Jahirat 2019

निवड प्रक्रिया (Selection Process):

Selection will be based on

  • Selections would be made on the basis of Written Examination.
  • The CTET examination will be of objective type Multiple Choice Question (MCQ’s).

परीक्षा पैटर्न  (Exam Process):

मदत क्रमांक (Help Desk): 
Kindly Refer Official Advertisement Given Below.

आधिकृत संकेत स्थल (Official Sites):

महत्वाचे दिनांक (Important Dates):

  • Online अर्ज सुरुवात दिनांक (Online Application Start Date): 19 August 2019
  • शेवट दिनांक (Last Date):  18 September 2019

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CTET Pariksha 2019 | CTET Online Application[ctet.nic.in] Jahirat 2019

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